作者: thomsonlee35 時間: 2008-10-16 22:14 標題: C number of digits
I learnt C in the class and I've a great difficulty.
The question is to find the number of digits of an input integer.
Can you help me? thanks
作者: MacMonster 時間: 2008-10-16 22:56
floor(log10(n) + 1)
注意: 個Result係double, 要轉番做integer. 零同負數會有問題.
作者: 99bbq 時間: 2008-10-16 22:58
Simplest method
divide by 10 then counting times of the digit until 0
作者: Guillo 時間: 2008-10-17 00:49
1234%10^0=0
1234%10^1=4
1234%10^2=34
1234%10^3=234
1234%10^4=1234
呢個方法都唔錯
作者: little_keung 時間: 2008-10-17 09:58
原帖由 MacMonster 於 2008-10-16 22:56 發表
floor(log10(n) + 1)
注意: 個Result係double, 要轉番做integer. 零同負數會有問題.
更簡單o既方法, 轉做 string , count string length .
更重要o既係, 呢個 algorithm 問題, 你諗掂o左個 algorithm 先考慮點樣 implement .
[ 本帖最後由 little_keung 於 2008-10-17 10:02 編輯 ]